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Tehnica mecanica |
2.Schema statica
P, P
, P
, P
, P
, P
, P
, P
= convoi de forte verticale
P, P
= convoi de forte transversale
P, P
= convoi de forte longitudinale
3.Actiuni
permanente + cvasipemanente(g)
greutate propie pod rulant
greutate sina de rulare
greutate propie prinderi
greutate balustrada
greutate propie grinda de franare
spatiu tehnic
circulatie pasarela
g= 6 kN/ml
n= 1.15
g= n
g
=1.15*6 = 6.9 kN/ml
variabile = actiuni ale podului rulant
Q = 20 tf
care lucreaza in grupa a III a de functionare.
Incarcari verticale (P)
P= n
P
n= 0.9
P= n
n
P
n= 1.2
= 1.3
pod rulant Q = 10 tf
P= n
P
= 0.9*113 = 101.7 kN
P= n
P
= 0.9*38 = 34.2 kN
P= n
P
= 0.9*131 = 117.9 kN
P= n
P
= 0.9*55 = 49.5 kN
P= n
n
P
= 1.2*0.9*1.3*113 = 158.65 kN
P= 1.2*0.9*1.3*38 = 53.35 kN
P= 1.2*0.9*1.3*131 = 183.92 kN
P= 1.2*0.9*1.3*55 = 77.22 kN
Pod rulant Q = 20 tf
P= n
P
= 0.9*155 = 139.5 kN
P= n
P
= 0.9*45 = 40.5 kN
P= n
P
= 0.9*185 = 166.5 kN
P= n
P
= 0.9*65 = 58.5 kN
P= n
n
P
= 1.2*0.9*1.3*155 = 217.62 kN
P= 1.2*0.9*1.3*45 = 63.18 kN
P= 1.2*0.9*1.3*185 = 259.74 kN
P= 1.2*0.9*1.3*65 = 91.26 kN
Incarcari orizontale transversale (P)
P= n
P
n= 0.9
P= n
n
P
n= 1.3
= 2.2 (10 tf)
= 1.8 (20 tf)
pod rulant Q = 10 tf
P=
(Q + G
) =
(100+30) = 3.25 kN
P= n
P
= 0.9*3.25 = 2.92 kN
P= n
n
P
= 1.3*0.9*2.2*3.25 = 8.36 kN
pod rulant Q = 20 tf
P=
(Q + G
) =
(200+47) = 6.17 kN
P= n
P
= 0.9*6.17 = 5.55 kN
P= n
n
P
= 1.3*0.9*1.8*6.17 = 12.99 kN
Incarcari orizontale longitudinale (P)
P= n
P
n= 0.9
P= n
n
P
n= 1.3
= 2.2 (10 tf)
= 1.8 (20 tf)
pod rulant Q = 10 tf
P=
P
=
*131 = 13.1 kN
P= P
= 131 kN
P= n
P
= 0.9*13.1 = 11.79 kN
P= n
n
P
= 1.3*0.9*2.2*13.1 = 33.72 kN
pod rulant Q = 20 tf
P=
P
=
*185 = 18.5 kN
P= P
= 185 kN
P= n
P
= 0.9*18.5 = 16.65 kN
P= n
n
P
= 1.3*0.9*1.8*18.5 = 38.96 kN
4.Eforturi
A'= 5600 mm
B'= 7100 mm
y =
= 1325 mm
A + y + A'= 5300 + 1325 + 5600 = 12225 mm > t = 9000 mm
Rezultanta fortelor :
R = P+ P
= 217.62 + 259.74 = 477.36 kN
Pozitia lui R :
PA' = Rx
217.62*5600 = 477.36*x x = 2552.94
2553 mm
A'- x = 5600 - 2553 = 3047 mm > x c = x = 2553 mm
= 0: 477.36*(4500-1276.5)-R
*9000 = 0
R
= 170.97 kN
R= R - R
= 477.36-170.97 = 306.39 kN
M= 306.39*(4500+1276.5)-477.36*2553 = 551.16*10
kNmm = 551.16 kNm
M
= 64.24 kNm
M= M
+ M
= 551.16+64.24 = 615.4 kNm
T
= 337.44 kN
T= T
-6.9*(4.5+1.2765-5.6) = 336.22 kN
T= T
- P
= 336.22-217.62 = 118.6 kN
T= T
-6.9*5.6 = 118.6-6.9*5.6 = 79.96 kN
T= T
- P
= 79.96-259.74 = - 179.78 kN
T= T
-6.9*(4.5-1.2765) = - 202.02 kN
T= T
+ R
Momentul dat de fortele orizontale transversale:
= 0: 12.99*0.1765+12.99*(0.1765+5.6)-r
*9 = 0
r
= 8.59 kN
r= 2 P
- r
= 2*12.99-8.59 = 17.39 kN
M= 17.39*(0.1765+5.6)-12.99*5.6 = 27.7 kNm
OL37 R = 220 N/mm
W=
=
= 3*10
mm
propun t= 8 mm
h= 1.15
= 1.15
= 704.22 mm
h
= 750 mm
=
= 93.75
O.K.
A=
- 0.16 h
t
=
- 0.16*750*8 = 3040 mm
A= b t
propun t
2.5) t
20 mm
t
= 12 mm
b = =
= 253.33 mm
b = 260 mm
aleg KP 80
b= 95 mm
b= 41 mm
b= 2(b
+ b
) + 2 (25
30) = 2*(95+41)+2*29 = 330 mm
b b
aleg b = 330 mm
=
= 13.41 < 15 O.K.
Verificarea rezistentei grinzii
P + g
M
=
z
R
I=
+ 2bt
(
)
+ 2
=
= + 2*330*12*(
)
+2*
= 0.143*10
mm
=
* 387 = 166.42
167 N/mm
< R = 220 N/mm
O.K.
=
R
= 0.6 R
T= max (T
, T
) = max (79.96; 179.78) = 179.78 kN
=
= 29.96 N/mm
< R
= 0.6*220 = 132 N/mm
O.K.
=
1.1 R
=
=
=
= 161.25 N/mm
=
= 169.39 N/mm
< 1.1 R = 1.1*220 = 242 N/mm
O.K.
= P
R
P= max ( P
, P
) = 259.74 kN
x = 50+2(h+ t
) = 50+2(130+12) = 334 mm
= 259.74*10
*
= 97.2
98 N/mm
< 220 N/mm
O.K.
P M
H = =
= 19.78 kN
d = 1400 mm
=
=
R
=
= 4.99
5 N/mm
< 220 N/mm
O.K.
P
=
=
R
=
= 9.83
10 N/mm
< 220 N/mm
O.K.
=
(M
) +
+
R
= 167+5+10 = 183 N/mm
< 220 N/mm
O.K.
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